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1449/1 Mathematics Paper 1 Oct./ ov. 2011 1 ¼ hours

JABATA PELAJARA MELAKA

PEPERIKSAA SELARAS AKHIR TAHU TI GKATA 4, 2011

MATHEMATICS
Paper 1 One hour and fifteen minutes

DO OT OPE THIS QUESTIO PAPER U TIL YOU ARE TOLD TO DO SO 1. This question paper consists of 40 questions. 2. Answer all questions. 3. Answer each question by blackening the correct space on the answer sheet. 4. Blacken only one space for each question. 5. If you wish to change your answer, erase the blackened mark that you have done. Then blacken the space for the new answer . 6. The diagrams in the questions provided are not drawn to scale unless stated. 7. A list of formulae is provided on pages 2 and 3. 8. You may use a non-programmable scientific calculator.

This question paper consists of 28 printed pages

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2 MATHEMATICAL FORMULAE

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The following formulae may be helpful in answering the questions. The symbols given are the ones commonly used. RELATIO S 1 2 3 4 a m × a n = a m+ n a m ÷ a n = a m−n

(a m ) n = a mn
A −1 =

1  d − b   ad − bc  − c a   
n( A) n (S )

5 6
7

P ( A) =

P ( A' ) = 1 − P( A)
Distance = ( x 2 − x1 ) 2 + ( y 2 − y1 ) 2

8

 x1 + x 2 y1 + y 2  ,  Midpoint , ( x, y ) =  2   2 Average speed =

9

distance travelled time taken

10

Mean = Mean =

sum of data number of data

11 12

sum of(class mark × frequency) sum of frequencie s

Pythagoras Theorem c2 = a2 + b2

13

m=

y 2 − y1 x 2 − x1

14

m=−

y − int ercept x − int ercept

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3

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SHAPES A D SPACE

1 2 3 4 5 6 7 8

Area of trapezium =

1 × sum of parallel sides × height 2

Circumference of circle = πd = 2πr
2 Area of circle = πr

Curved surface area of cylinder = 2πrh
2 Surface area of sphere = 4πr

Volume of right prism = cross sectional area × length Volume of cylinder = πr 2h Volume of cone = 1 2 πr h 3 4 3 πr 3 1 × base area × height 3

9

Volume of sphere =

10 11 12

Volume of right pyramid =

Sum of interior angles of a polygon = (n – 2) × 180º arc length angle subtended at centre = circumference of circle 360 o area of sector angle subtended at centre = area of circle 360 o Scale factor, k = PA' PA

13

14 15

Area of image = k2 × area of object

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4 Answer all questions.
Jawab semua soalan.

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1

Round off 3.028 correct to three significant figures. Bundarkan 3.028 betul kepada tiga angka bererti. A 3.02 B 3.03 C 3.020 D 3.030 Given that 0.000 078 = m x 10n , where m x 10n is a number in standard form. State the value of m and of n. Diberi bahawa 0.000 078 = m x 10n, dengan keadaan m x 10n adalah nombor dalam bentuk piawai. yatakan nilai m dan nilai n. A m = 7.8, n = − 5 B m = 7.8, n = 5 C m = 78, n = − 6 D m = 78, n = 6 0.078 = 2.6 × 10 5 A 3 x 10-3 B 3 x 10-4 C 3 x 10-6 D 3 x 10-7

2

3

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5

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The total population of Malaysia in the year 2010 is 26.37 million. It is given that the number of people who are 60 years of age and above is 4.2% of the total population. Calculate the number of people who are below 60 years of age. [1 million = 106] Jumlah populasi Malaysia dalam tahun 2010 ialah 26.37 juta. Diberi bahawa bilangan orang yang berumur 60 tahun dan ke atas adalah 4.2% daripada jumlah populasi. Hitung bilangan orang yang berumur di bawah 60 tahun. [ I juta = 106 ] A 1.11 x 106 B 1.11 x 107 C 2.53 x 106 D 2.53 x 107

5

Evaluate: ilaikan: 8.32 x 10-5 – 7.6 x 10-6 .

A B C D 6

7.56 x 10-6 8.56 x 10-6 7.56 x 10-5 8.56 x 10-5

(2x – y)2 – x(x + y) = A 3x2 – y2 – 3xy B 3x2 + y2 – 3xy C 3x2 – y2 – 5xy D 3x2 + y2 – 5xy

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7 In Diagram 7, HIJKLM is a regular hexagon. JKLO is a rhombus and JL is the diagonal of the rhombus. Dalam Rajah 7, HIJKLM ialah sebuah heksagon sekata. JKLO ialah sebuah rombus dan JL ialah pepenjuru bagi rombus itu.

Diagram 7/Rajah 7 Find the value of x + y. Cari nilai bagi x + y . A 300 290 B C 270 D 240

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7

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In Diagram 8,...

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Keywords

+5 -1 -3 -4 -5 -6 -7 .. /rajah 0 0.000 0.078 0.643 0.766 0.839 078 1 1.11 1.191 1.2 1.4 1.6 10 106 107 10n 11 11/rajah 110 115 117 12 12/rajah 13 13/rajah 130 135 14 1449/1 1449/2 15 15/rajah 150 16 16/rajah 160 165 17 17/rajah 18 18/rajah 180 180º 18m2n2 18m3n2 19 19/rajah 2 2.0 2.53 2.6 20 2010 2011 205 21 22 23 24 240 25 26 26.37 27 270 28 29 29/rajah 290 2h 2rs 2x 2πr 2πrh 3 3.02 3.020 3.028 3.03 3.030 30 30/jadual 300 31 32 33 33/rajah 34 35 35/rajah 36 360 37 37.5 38 38/jadual 39 3mn 3x2 3xy 4 4.2 40 45 47 4πr 5 50 51 52 55 57 5xy 6 60 65 6m2n3 7 7.56 7.6 7.8 7/rajah 70 75 78 8 8.32 8.56 8/rajah 80 85 9 9/rajah 90 9m3n4 9mn2 a2 abcd abf ad adalah afgb age ahmad ajah aka akhir alloc amakan angka angl answer antara apakah arc area ata atau averag b b2 bag bagi bahagian bahawa bar base batang bawah bc beg bentuk berapakah bererti berikut berlorek bernilai bernombor berpusat bersudut berumur betul biji bilangan black blacken book box boxes/kotak bracket buah buka bukan buku bulatan bundarkan bungkus c c2 calcul cantuman card cari carikan carta caus ce cent centr chang chart cipta circl circumfer class cm cm2 cm3 coin common complet cone consist contain convers coordin correct cost cross cross-sect cuboid curv cylind d dalam dan dari daripada data decim dengan depress determin di diagon diagram diambil diamet dibaca diberi diberitahu diluki dipilih distanc ditandai done dongak draw drawn dua duit e element elev empat enam end enlarg equat equilater eras ercept evalu examin f factor fifteen figur find five follow form formula four frequenc frequenci full g ga gambar gandaan ganjil gari garis-gari gef get gga given gkata gradient graf gram graph grid group gula gula-gula guli guna h hak half hand harga health height heksagon helai help hexagon hijklm hitam hitung hitungkan horizont hour ialah identifi ilai ilaikan imag imej implic implikasi incomplet inequ inform ini int integ intercept interior invigil isbah isipadu itu ja jabata jadual jawab jawapan jika jisim jklo jl join jpm jumlah juta k k2 kad kad-kad kawasan ke keadaan kebarangkalian kecerunan kedua kedua-dua kemeja kemudiannya kenalpasti kepada kepe keratan kerta ketaksamaan klm koordinat kotak kuadratik kuboid l lengkap lengkok length lie lihat lima line linear list lmrq lorekkan ls lsk lua lurus m maka maklumat malaysia manakah manakala mani marbl mark markah mase mass mathemat may mean median melaka memasukkan memilih memuaskan menara mengandungi mengeluarkan menggunakan mengufuk menunjukkan mewakili midpoint million min minut mn multipl murid n name new nilai nilai-nilai nombor non non-programm number o object obtain oct odd oleh one op ope orang ot ov p pa packet pada page pai palang panjang panjangnya paper parallel pelajara pembesaran pentagon peopl pepej pepenjuru peperiksaa perdana perimet permukaan perpuluhan persamaan piawai pick pie pintasan pintasan-i pintasan-x place plane point pole polygon popul populasi pos pq pqr pqrs prime print prism prisma probabl problem programm provid pto pupil pusat put putih pyramid pythagora q qj qrs qrwv qs quadrat quadrilater questio question r rajah random ratio rawak read region regular relatio renta repres respect rhombus right right-angl ringkaskan rm rm27 rm90 rombus round rs rst ruang sama satah satisfi satu scale scientif sebelah sebiji sebuah secara section sector segiempat segitiga sehelai sehi sehingga sekata sekep sektor sekumpulan selara select selesaikan seluruh semesta semi semicircl seminggu semua sen sentenc separuh seragam serentak set shade shape sheet shirt show shown side signific silind simplifi simultan sisi sisiempat six slm slr sml soala soalan solid solv space speed sphere squar srl standard state straight suatu subtend sudut sulit sum surfac sweet syil symbol t-shirt tabl tahu tahun take taken tamat tan tangen tangent tapak tegak tempat tempoh tentukan terdiri terletak tersebut theorem thirti three ti tiang tidak tiga til time titik titik-titik told total towel tower translasi translat trapezium travel triangl tuala tunduk two u umber uniform unit univers unless unsur unsur-unsur untuk uqr use valu venn vertic volum vqr vqu vru vuq week white whole wish work write x x-intercept x1 x2 y y-intercept y1 y2 yang yatakan year ξ πd πr